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IBPS Clerk Prelims Model Paper 1
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© examsnet.com
Question : 46
Total: 100
The angles of a quadrilateral are in the ratio of 2 : 4 : 7 : 5. The smallest angle of the quadrilateral is equal to the smallest angle of a triangle. One of the angles of the triangle is twice the smallest angle of the triangle. What is the second largest angle of the triangle?
80°
60°
120°
62º
Cannot be determined
Validate
Solution:
Let the angle of quadrilateral
be 2xº, 4xº, 7xº and 5xº then,
2x + 4x + 7x + 5x = 360°
⇒ 18x = 360°
⇒ x =
360
°
18
= 20°
∴ Smallest angle of the triangle = 2xº
= 2 × 20° = 40°
Second angle = 2 × 40 × = 80°
∴ Required angle
= (180° – 80° – 40°)
= 60°
© examsnet.com
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