Le t the 5 consecutive even numbers be x, (x + 2) (x + 4), (x + 6) and (x + 8) respectively, Then, x + x + 2 + x + 4 + x + 6 + x + 8 = 220 5x + 20 = 220 x = 40 Second lowest number of different sets = 2 × 40 - 37 = 43 ∴ Required sum = 42 + 43 + 44 + 45 + 46 = 220