(A)→(R), (S), (T): At steady-state (DC), C acts as an open (I = 0) and L acts as a short (
V1 = 0). In AC circuits, there is no steady-state and I ≠ 0. Also
V1 ∝ I.
(B)→(Q), (R), (S), (T):
• Option (Q):
V1 = 0,
V2 = V >
V1.
• Option (R): XL = 2πfL = 6.28 × 50 × 6 ×
10−3 = 1.884 < R = 2.
Therefore,
V2 >
V1.
• Option (S):
XC =
=
= 1061.5 Ω >
XL.
Therefore,
V2 >
V1.
• Option (T):
XC = 1061.5 Ω < R = 1000 Ω, therefore,
V2 >
V1.
(C)→(P), (Q): Since L acts as a short at steady state
V1 = 0 and
V2 = V.
(D)→(Q), (R), (S), (T): Same reasons as explained above: I ≠ 0.
The voltage drop across all three circuit elements is proportional to I.