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IIT JEE Advanced 2012 Paper 1
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Question : 3
Total: 60
A biconvex lens is formed with two planoconvex lenses as shown in the figure. Refractive index n of the first lens is 1.5 and that of the second lens is 1.2. Both curved surface are of the same radius of curvature R = 14 cm. For this biconvex lens, foran object distance of 40 cm, the image distance will be
–280.0 cm
40.0 cm
21.5 cm
13.3 cm
Validate
Solution:
For this biconvex lens, for an object distance of 40 cm, the image distance is calculated as follows:
P
T
=
(
1.5
−
1
)
(
1
14
−
0
)
+
(
1.2
−
1
)
(
0
−
1
−
14
)
=
0.5
14
+
0.2
14
=
1
20
That is, f = +20 cm. Therefore,
1
v
−
1
−
40
=
1
20
⇒
1
v
=
1
20
−
1
40
=
1
40
Therefore, v = 40 cm.
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