A small block is connected to one end of a massless spring of un-stretched length 4.9 m. The other end of the spring (see the figure) is fixed. The system lies on a horizontal frictionless surface. The block is stretched by 0.2 m and released from rest at t = 0. It then executes simple harmonic motion with angular frequency ω = (π /3) rad/s. Simultaneously, at t = 0, a small pebble is projected with speed v from point P at an angle of 45° as shown in the figure. Point O is at a horizontal distance of 10 m from O. If the pebble hits the block at t = 1 s, the value of v is (take g = 10 {m/s}²) [JEE Adv 2012 P1]

Question

Examsnet · Accepted Answer

Correct Answer is : 50{50}50​ m/s

IIT JEE Advanced 2012 Paper 1