According to the reaction P4+NaOH+3H2O → PH3+3NaH2PO2 oxidation state of phosphorus in P4 is zero while in PH3 it is −3 and in NaH2PO2, it is +1. This shows that this is a type of disproportionation reaction because there is an increase as well as decrease in the oxidation state of phosphorus.