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IIT JEE Advanced 2012 Paper 2

Paragraph for Questions 31 and 32:
The electrochemical cell shownbelow is a concentration cell.
M|M2+ (saturated solution of a sparingly soluble salt, MX2) || M2+ (0.001 mol‌d‌m−3)|M
The emf of the cell depends on the difference in concentrations of M2+ ions at the two electrodes. The emf of the cell at 298 K is 0.059 V.

Question : 32

Total: 60

The solubility product (Ksp; mol3dm−9) of MX2 at 298 K based on the information available for the given concentration cell is (take 2.303 × R × 298/F = 0.059 V).

1 × 10−15
4 × 10−15
1 × 10−12
4 × 10−12

Validate

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