Given that cost of a type of pastry is equal to the quantity bought if x,y,z are the no. of pastries bought of each type then x2+y2+z2=211 and x+y+z=23 Using options, option A = 10,9,4 i.e. 100+81+16=197 therefore cannot be the answer option B= 11, 9, 3 i.e. 121+81+9=211 Therefore is our answer option C = 10, 8 , 5 i.e. 100+64+25=189 therefore cannot be the answer option D = 11, 8, 4 i.e. 121+64+16=201 therefore cannot be the answer Therefore our answer is option 'B'