(d) There are two vowels I and A in RIYADH (i) No. of ways in which 2 vowels can be arranged together in RIYADH = 5! × 2! = 240 Hence statement (i) is not true. (ii) Total no. of arrangements = 6! = 720. ∴ No. of ways in which vowels do not occur together = 720 – 240 = 480 Hence statement (ii) is also not true.