Let Sandra, David and Mary each has s, d and 11 respectively. After the first distribution, David has d + d = 2d, Mary has 11 + 11 = 22 and Sandra has s - d - 11. After the second distribution, Sandra has 2×(s - d - 11) , mary has 2×22 = 44 and david has 2d (s - d - 11) 22=3d s 11. After the third distribution, Sandra has 2×2(s - d - 11), david has 2×(3d s 11) and mary has 44 2(s - d - 11) (3d - s - 11) = 77 - s - d It is given that finally Mary has Rs.17. So, 77 - s - d =17. ⇒ s + d = 60 ⇒ s + d + 11 = 60 + 11 = 71.