All the three gates are represented by A, C, and T. Now A is 144 du away from N and C is 7.5 du away from E and T is 135 du away from S, and all are in straight line. △AOC,△AST are similar triangles. So ⇒ AO/OC = AS/ST. ⇒ (144 + r) / (r + 7.5) = (144+2r)/ 135. Solving we get r = 90. So diameter of the wall = 180 du.