Given the code format: public static void main (String [] args) { String names [] = {"Thomas", "Peter","Joseph"}; String pwd [] = new String [3]; int idx = 0; try { for (String n: names) { pwd [idx] = n.substring (2, 6); idx++; } } catch (Exception e) { System.out.println("Invalid Name"); } for (String p: pwd) { System.out.println (p); } } What is the result?

Question

Given the code format:   public static void main (String [] args) {      String names [] = {"Thomas", "Peter","Joseph"};     String pwd [] = new String [3];     int idx = 0;      try {       for (String n: names) {         pwd [idx] = n.substring (2, 6);         idx++;       }     }     catch (Exception e) {       System.out.println("Invalid Name");     }        for (String p: pwd) {       System.out.println (p);     }   }   What is the result?

Examsnet · Accepted Answer

Correct Answer is : Invalid Name omas null null

Java SE 8 Programmer 1Z0–808 Practice Full Test 1