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JEE Advanced 2014 Paper 1
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© examsnet.com
Question : 2
Total: 60
At time t = 0, terminal A in the circuit shown in the figure is connected to B by a key and an alternating current
I
(
t
)
=
I
0
cos
(
ω
t
)
,with
I
0
=
I
A
and
ω
=
500
rad/s starts flowing in it with the initial direction shown in the figure.At
t
=
7
π
6
ω
, the key is switched from B to D. Now onwards only A and D are connected. A total charge Q flows from the battery to charge the capacitor fully. If C
=
20
μ
F
,
R
=
10
Ω
and the battery is ideal with emf of 50 V, identify the correct statement(s).
Magnitude of the maximum charge on the capacitor before
t
=
7
π
6
ω
is
1
×
10
−
3
C
The current in the left part of the circuit just before
t
=
7
π
6
ω
is clockwise
Immediately after A is connected to D,the current in R is
10
A
Q
=
2
×
10
−
3
C
Validate
Solution:
As current leads voltage by
π
2
in the given circuit initially, then ac voltage can be represented as
V
=
V
0
sin
ω
t
∴
q
=
C
V
0
sin
ω
t
=
Q
sin
ω
t
where, Q
=
2
×
10
−
3
C
•At
t
=
7
π
6
ω
;
I
=
−
√
3
2
I
0
and hence current is anticlockwise
• Current 'i' immediately after
t
=
7
π
6
ω
is
i
=
V
c
+
50
R
=
10
A
•Charge flow
=
Q
final
−
Q
(
7
π
/
6
ω
)
=
2
×
10
−
6
C
Hence C & D are correct options
© examsnet.com
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