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JEE Advanced 2015 Paper 2
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© examsnet.com
Question : 15
Total: 60
A parallel plate capacitor having plates of area S and plate separation d,has capacitance
C
1
in air.When two dielectrics of different relative permittivities
(
ε
1
=
2
and
ε
2
=
4
)
are introduced between the two plates as shown in fig,the capacitance becomes
C
2
.the ratio
C
2
C
1
is
6
5
5
3
7
5
7
3
Validate
Solution:
C
10
=
4
ε
0
S
2
d
2
=
4
ε
0
S
d
C
20
=
2
ε
0
S
d
,
C
30
=
ε
0
S
d
1
C
′
10
=
1
C
10
+
1
C
10
=
d
2
ε
0
S
[
1
+
1
2
]
⇒
C
′
10
=
4
ε
0
S
3
d
C
2
=
C
30
+
C
′
10
=
7
ε
0
S
3
d
C
2
C
1
=
7
3
© examsnet.com
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