Given OP = OR = 3 and OPQR is a square ⇒OQ=3√2⇒OT=
3
√2
and ST=3 Using ΔSOT, tanθ=
ST
OT
=√2⇒θ=tan−1√2 clearly, equation of plane containing triangle OQS is Y – X = 0 Also, length of perpendicular from P to the plane containing the triangle OQS is PT=