The ends Q and R of two thin wires, PQ and RS, are soldered (joined) together. Initially each of the wires has a length of 1m at 10°C. Now the end P is maintained at 10°C, while the end S is heated and maintained at 400°C. The system is thermally insulated from its surroundings. If the thermal conductivity of wire PQ is twice that of the wire RS and the coefficient of linear thermal expansion of is 1.2 × 10^{-5} \, {K}^{-1},the change in length of the wire PQ is [JEE Adv 2016 P2]

Question

Examsnet · Accepted Answer

Correct Answer is : 0.780.780.78 mm

JEE Advanced 2016 Paper 2