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JEE Advanced 2016 Paper 2
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© examsnet.com
Question : 4
Total: 54
There are two vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The Vernier scale of one of the calipers
(
C
1
)
) has 10 equal divisions that correspond to 9 mainscale divisions. The Vernier scale of the other caliper
(
C
2
)
has 10 equal divisions that correspond to 11 main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers
C
1
and
C
2
respectively,are
[JEE Adv 2016 P2]
2.87
and
2.86
2.87
and
2.87
2.87
and
2.83
2.85
and
2.82
Validate
Solution:
For calliper
C
1
10 VSD = 9MSD
LC = 1MSD - 1VSD
LC = 1MSD - 1VSD
LC=0.01 cm
Measured value =min scale reading+vernier scale reading
=
(
2.8
+
7
×
0.01
)
cm
=
2.87
cm
For caliper
C
2
10 VSD=11 MSD
LC
=
0.01
cm
Measured value
=
{
2.8
+
(
10
−
7
×
0.01
)
}
cm
=
2.83
cm
© examsnet.com
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