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JEE Advanced 2017 Paper 1

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An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams in column 3 of the table. Consider only the path from state 1 to state 2. W denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic processes. Here γ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas in n.
Column 1Column 2Column 3
(I) W121γ1(P2V2P1V1)W_{1\rightarrow2}\frac{1}{\gamma-1}(P_2V_2-P_1V_1)(i) Isothermal(P)
(II) W12=P2V2+PV1W_{1\rightarrow2}=-P_2V_2+PV_1(ii) Isochoric(Q)
(III) W12=0W_{1\rightarrow2}=0(iii) Isobaric(R)
(IV) W12=nRTln(V2V1)W_{1\rightarrow2}=-nRT\ln\left(\frac{V_2}{V_1}\right)(iv) Adiabatic(S)
Section: Physics
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