Net power radiated =σa(T4−T04) For small temperature difference,ΔT=T−T0 P(Net)=σA[(T0+ΔT)4−T04]=σAT04[(1+
ΔT
T0
)4−1]=σAT04[
4ΔT
T0
] ∴P(Net)=4σAT03(T−T0) (A) From the above result, P(Net) decreases with A (B) Peak shits to shorter wave lengths for rise in temperature (C) P(Radius)=σAT4=σA(T0+10)4>460watt Hence (C) is incorrect answer If P(Net) is taken, then (C) will be correct (D) Energy radiated by a body is dependent only on its own temperature, not the temperature of surroundings. Hence (D) is incorrect. If P(Net) is taken, then from the calculation shown above, (D) will also be correct