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JEE Advanced 2019 Paper 1
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© examsnet.com
Question : 12
Total: 54
In the circuit shown, initially there is no charge on capacitors and keys
S
1
and
S
2
are open. The values of the capacitors are
C
1
=
10
µ
F
,
C
2
=
30
µ
F
and
C
3
=
C
4
=
80
µ
F
Which of the statement(s) is/are correct?
If key
S
1
is kept closed for long time such that capacitors are fully charged, the voltage across the capacitor
C
1
will be 4V.
At time
t
=
0
the key
S
1
is closed, the instantaneous current in the closed circuit will be 25mA
If key
S
1
is kept closed for long time such that capacitors are fully charged, the voltage difference between points P and Q will be 10V.
The key
S
1
is kept closed for long time such that capacitors are fully charged. Now key
S
2
is closed, at this time, the instantaneous current across 30Ω resistor (between points P and Q) will be 0.2A (round off to 1st decimal place)
Validate
Solution:
C net
=
40
×
10
40
+
10
=
8
µ
F
⇒
Q
=
40
µ
C
V across
C
1
=
40
µ
C
10
µ
F
=
4
V
(at steady state)
Just after
S
1
is closed,
i
=
5
30
+
70
+
100
=
25
m
A
Long time after
S
1
is closed,
V
P
Q
=
V
C
1
=
4
V
Just after
S
2
is closed
−
10
+
30
(
i
1
+
i
2
)
+
4
+
70
i
,
=
0
−
10
+
30
(
i
1
+
i
2
)
−
1
2
+
5
+
30
i
2
+
100
i
2
−
1
2
=
0
30
i
2
+
100
i
1
=
6
60
i
2
+
30
i
1
=
6
i
1
+
i
2
=
0.05
A
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