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JEE Advanced 2020 Concept Recapitulation Test 1 Paper 1
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© examsnet.com
Question : 18
Total: 54
Four wires of equal length
8
m
are arranged as shown in the figure. Wires, 2,3 and 4 are of equal cross sectional area and wire 1 is of half the cross section of these wires. By how much distance pointer at point 5 must be moved to get null point?
Your Answer:
Validate
Solution:
For getting null point
R
1
R
3
=
R
2
R
4
as
R
2
=
R
4
R
1
=
R
3
Let the pointer at point 5 is moved to left by distance
x
to get nul point as shown in the figure. If resistance per unit length of wire 3 is
r
then thatof wire 1 will be
2
r
.
(
8
−
x
)
2
r
=
x
×
2
r
+
8
×
r
4
x
=
8
x
=
2
m
© examsnet.com
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