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JEE Advanced 2020 Concept Recapitulation Test 1 Paper 1
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© examsnet.com
Question : 2
Total: 54
A traveling wave pulse is given by
y
=
6
2
+
(
x
+
3
t
)
2
where symbols have their usual meanings,
x
,
y
are in metre and
t
is in second. Then
the pulse is traveling along +ve
x
-axis with velocity
3
m
∕
s
the pulse is traveling along -ve
x
-axis with velocity
3
m
∕
s
the amplitude of the wave pulse is
3
m
the pulse is a symmetric pulse
Validate
Solution:
Sign between
x
and
t
is
⊕
hence wave is propagating in negative
x
direction.
wave velocity
=
coefficient of
t
coefficient of
x
=
3
1
Max value of
y
is amplitude,
y
has maximum value when denominator isleast i.e.
when
(
x
+
3
t
)
2
is zero
y
=
3
m
shape of pulse is given by
y
=
6
2
+
x
2
(
t
=
0
)
shape of pulse is symmetrical out y-axis
© examsnet.com
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