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JEE Advanced 2020 Concept Recapitulation Test 1 Paper 1
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© examsnet.com
Question : 7
Total: 54
The potential energy
ϕ
in joule of a particle of mass
1
k
g
moving in the
x
−
y
plane, obeys the law
ϕ
=
3
x
+
4
y
, where
(
x
,
y
)
are the coordinate of the particle in metre. If the particle is at rest at
(
6
,
4
)
at time
t
=
0
, then (only conservative force are acting on particle).
the particle has constant acceleration
the work done by the conservative forces from position of rest of the particle to the instant of the particle crossing
x
axis is
25
J
the speed of the a particle when it crosses the
y
axis is
10
m
s
−
1
the coordinates of the particle at time
t
=
4
s
are
(
−
18
,
−
28
)
Validate
Solution:
→
F
=
3
∧
i
−
4
∧
j
,
W
con.
f
=
U
1
−
U
t
=
34
−
9
=
25
&
1
2
m
v
2
−
16
=
34
© examsnet.com
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