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JEE Advanced 2020 Concept Recapitulation Test 2 Paper 2
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© examsnet.com
Question : 18
Total: 54
An artificial satellite of mass
m
is moving in a circular orbit at a height
h
equal to radius of the earth from the earth's surface. Suddenly due to internal explosion the satellite breaks into two parts of equal masses. One part of the satellite stops just after the explosion and then falls to the surface of the earth. If find the increase in mechanical energy of the system (satellite + earth) due to explosion. (Acceleration due to gravity on the earth's surface is g) is
n
. (mgR) then find the value of 'n'.
Your Answer:
Validate
Solution:
Applying conservation of momentum
m
v
=
m
2
×
0
+
m
2
v
′
⇒
v
′
=
2
v
Increase in mechanical energy of the system
=
1
2
m
2
(
2
v
)
2
−
1
2
m
v
2
=
1
2
m
v
2
=
G
M
m
2
×
(
2
R
)
=
m
g
R
2
4
R
=
m
g
R
4
© examsnet.com
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