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JEE Advanced 2020 Concept Recapitulation Test 3 Paper 1

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Answer questions 11,12 and 13 by appropriately matching the information given in the three columns of the following table.
A charged particle (elelctron or proton) is introduced at the origin (0,0,0) with a given initial velocity
→
v
, electric field
→
E
 and magnetic field
→
B
 are given in column 1,2,3 respectively. The quantities E0,B0 are +ve in nature.
 Column - 1  Column - 2  Column - 3
 (I) Electron with
→
V
=2‌
E0
B0
∧
i
  (i)
→
E
=E0
⋀
K
  (P)
→
B
=−B0
∧
i
 (II) Electron with
→
V
=‌
E0
B0
⋀
j
  (ii)
→
E
=−E0
⋀
j
  (Q)
→
B
=−B0
∧
i
 (III) Proton with
→
V
=0		  (iii)
→
E
=−E0
⋀
i
  (R)
→
B
=−B0
∧
j
 (IV) Proton with
→
V
=‌
2E0
B0
∧
i
  (iv)
→
E
=E0
⋀
i
  (S)
→
B
=−B0
∧
k
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