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JEE Advanced 2020 Concept Recapitulation Test 3 Paper 2
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© examsnet.com
Question : 14
Total: 54
Two identical disc
A
and
B
of equal mass '
m
' and radius 'R' are connected by a massless rod. The centres of disc C of mass '
m
′
and radius
4
R
and disc
B
are connected by massless rod which makes an angle of
30
∘
with the horizontal. There is no slipping between each disc and surface on which it rolls. When angular speed of disc
C
is
ω
0
, rod connecting disc
A
and
B
makes an angle
60
∘
with horizontal. Then, at the given instant
Angular speed of disc
A
is
4
ω
0
∕
√
3
Angular speed of disc
A
is
2
ω
0
∕
√
3
The total kinetic energy of the system is
28
m
ω
0
2
R
2
The total kinetic energy of the system is
26
m
ω
0
2
R
2
Validate
Solution:
Let angular velocity of disc
A
and
B
be
ω
1
and
ω
2
respectively. Component of velocity of points on rod along rod would be same
ω
2
R
cos
30
∘
=
4
ω
0
R
cos
30
∘
ω
2
=
4
ω
0
ω
1
R
cos
30
∘
=
ω
2
R
cos
60
∘
ω
1
=
4
ω
0
√
3
K
=
1
2
×
3
2
m
R
2
ω
1
2
+
1
2
×
3
2
m
R
2
ω
2
2
+
1
2
×
3
2
m
16
R
2
ω
0
2
=
28
m
ω
e
2
R
2
© examsnet.com
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