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Paragraph for Question Nos. 33 and 34
A quantity of25 m L of solution containing both F e 2 * and F e 3 + ions is titrated with 25 m L of 0.0200 M K M n O 4 2 n dilute H 2 S O 4 . As a result all the F e 2 * ions are oxidiced to F e 3 * ions. Next 25 m L of the original solution is treated with zn metal. Finally, the solution requires 40 m L of the same K M n O 4 solution for oxidation to F e 3 * . M n O 4 − + 5 F e i r + 8 H * ⟶ M n 2 + 5 F e 2 t + 4 H 2 O
A quantity of
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