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JEE Advanced 2020 Concept Recapitulation Test 4 Paper 1
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© examsnet.com
Question : 50
Total: 54
If
f
(
y
)
=
lim
n
→
∞
n
∑
n
=
1
e
n
+
y
(
e
−
1
)
(
e
n
−
1
)
(
e
n
+
1
−
1
)
then find the value of
1
∫
0
f
(
x
)
d
x
.
Your Answer:
Validate
Solution:
f
(
y
)
=
lim
n
→
∞
n
∑
n
=
1
e
y
e
n
(
e
−
1
)
(
e
n
−
1
)
(
e
n
+
1
−
1
)
=
e
y
lim
n
→
∞
n
∑
n
=
1
(
(
e
n
+
1
−
1
)
−
(
e
n
−
1
)
(
e
n
−
1
)
(
e
n
+
1
−
1
)
)
=
e
y
lim
n
→
∞
n
∑
n
=
1
(
1
e
n
−
1
e
n
+
1
−
1
)
=
e
y
lim
n
→
x
(
(
1
e
−
1
−
1
e
2
−
1
)
+
(
1
e
2
−
1
−
1
e
3
−
1
)
+
.
.
.
.
.
.
+
(
1
b
n
−
1
−
1
e
n
+
1
−
1
)
)
=
e
y
e
−
1
1
∫
0
f
(
x
)
d
x
=
1
e
−
1
1
∫
0
e
x
d
x
=
1
© examsnet.com
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