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JEE Advanced 2020 Concept Recapitulation Test 4 Paper 2

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Question : 5

Total: 54

50gm ice at −10∘C is mixed with 20gm steam at100∘C. When the mixture finally reaches its steady state inside a calorimeter of water equivalent 1.5gm then: [Assume calorimeter was initially at 0∘C, Take latent heat of vaporization of water =540 callgm, Latent heat of fusion of water =80 cal\/gm, Specific heat capacity of water =1cal∕gm−‌∘C, Specific heat capacity of ice = 0.5cal∕gm−‌∘C]

Mass of water remaining is: 67.4gm
Mass of water remaining is 67.87gm
Mass of steam remaining is 2.6gm
Mass of steam remaining is 2.13gm

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