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JEE Advanced 2020 Full Test 2 Paper 1
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© examsnet.com
Question : 12
Total: 54
A sound wave of frequency
v
travels horizontally to the right. It is reflected from a large vertical plane surface moving to the left with a speed
V
. The speed of sound in the medium is
c
.
The number of wave pulse striking the surface per second is
v
(
c
+
V
)
c
The wavelength of the reflected wave is
c
(
c
−
V
)
v
(
c
+
V
)
The frequency of the reflected wave is
v
(
c
+
V
)
(
c
−
V
)
The number of beats heard by a stationary listener to the left of the reflecting surface is
v
V
c
−
V
Validate
Solution:
Frequency observed by wall
f
′
=
v
c
+
V
C
(
moving observee
)
=number of pulse striking persecond
Frequency of reflected wave
f
′
′
=
f
′
c
C
−
V
=
v
C
+
V
C
−
V
Wavelength
f
′
′
=
f
′
c
C
−
V
=
v
C
+
V
C
−
V
© examsnet.com
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