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JEE Advanced 2020 Full Test 2 Paper 1
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© examsnet.com
Question : 16
Total: 54
A uniform rod of length
I
=
1
m
is free to move and rotate in gravity-free space. When an impulse is given to one end of the rod, perpendicular to its length, its centre of mass moves with velocity
v
=
1
m
∕
s
. What will be its angular velocity (in rad/s) about its centre of mass?
Your Answer:
Validate
Solution:
By linear momentum conservation impulse
(
J
)
=
m
V
.
By angular momentum conservation, angular impulse
=
J
λ
2
=
I
ω
So
m
v
λ
2
=
I
ω
or
ω
=
m
v
λ
2
I
=
m
v
λ
2
(
m
λ
2
12
)
=
6
v
λ
=
6
r
a
d
© examsnet.com
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