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JEE Advanced 2020 Full Test 2 Paper 1
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© examsnet.com
Question : 7
Total: 54
A chain of length
L
and mass per unit length
ρ
is piled on a horizontal surface. One end of the chain is lifted vertically with constant velocity by a force
P
.
P
as a function of height
x
of the end above the surface will be
ρ
(
g
x
+
v
2
)
.
No energy will loss in this process.
Work done by force will be
1
2
ρ
g
L
2
+
ρ
V
2
L
Loss in energy
1
2
ρ
g
L
v
2
Validate
Solution:
P
=
weight of the vertical part
+
force required to provide momentum to the part which is being lefted per unit time Hence,
P
=
δ
g
x
+
(
δ
v
d
t
)
v
d
t
P
=
δ
[
g
x
+
v
2
]
© examsnet.com
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