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JEE Advanced 2020 Full Test 2 Paper 2
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© examsnet.com
Question : 8
Total: 54
The radius of curvature of the left and right surface of the concave lens are
10
c
m
and
15
c
m
respectively. The radius of curvature of the mirror is
15
c
m
equivalent focal length of the combination is
−
18
c
m
equivalent focal length of the combination is
+
36
c
m
the system behaves like a concave mirror
the system behaves like a convex mirror
Validate
Solution:
P
glass
=
−
1
12
P
water
=
2
45
P
mirror
=
2
15
P
combination
=
−
2
P
lens
+
P
m
=
2
12
−
4
45
−
2
15
=
−
10
180
=
−
1
18
f
combination
=
−
18
c
m
Focal length is negative hence it behaved like a concave mirror.
© examsnet.com
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