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JEE Advanced 2020 Full Test 3 Paper 2

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Question : 10

Total: 54

Consider the decay ‌238‌Pu→‌234U+‌4‌He The atomic masses are given as
‌238.04955u238‌Pu ‌234.04095u234U ‌4.002633u4‌He
Neglecting the recoil of the residual nucleus

the kinetic energy of the α particle emitted is 5.58MeV
the kinetic energy of the α particle emitted is 5.58eV
conservation of electric charge is valid for the given reaction
conservation of electric charge is not valid for the given reaction

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