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JEE Advanced 2020 Full Test 4 Paper 1
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© examsnet.com
Question : 14
Total: 54
Two balls
A
and
B
of masses 1 kg each are connected by an inextensible massless string. The system is resting on a smooth horizontal surface. An impulse of
10
N
s
is applied to the ball
A
at an angle
30
∘
with the line joining two balls in horizontal direction as shown in the figure. Assuming that the string remains taut after the impulse, if the magnitude of kinetic energy of ball
A
is
175
k
.
Find the value of
K
.
Your Answer:
Validate
Solution:
Let
u
is the velocity of
A
and
B
along the string
10
cos
30
=
2
u
⇒
u
=
5
√
3
2
m
∕
s
Let
v
is velocity of
A
⟂
to the string.
10
sin
30
=
v
⇒
v
=
5
m
∕
s
∴
V
A
=
√
u
2
+
v
2
=
√
175
2
K
E
A
=
175
8
J
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