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JEE Advanced 2020 Full Test 4 Paper 2
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© examsnet.com
Question : 18
Total: 54
In a moving coil galvanometer, torque on the coil can be expressed as
τ
∝
i
,
where
i
is current through the wire. The rectangular coil of the galvanometer having number of turns
N
,
area
A
and moment of inertia I is placed in magnetic field
B
. The torsion constant of spring in the galvanometer is
C
and charge
Q
is passed through the coil almost instantaneously. If the maximum angle through which coil deflected is
K
N
A
B
Q
√
4
C
I
. (lgnore the damping in mechanical oscillations).
Your Answer:
Validate
Solution:
∫
τ
d
t
=
N
A
B
∫
i
d
t
I
ω
0
=
N
A
B
Q
.
.
.
.
.
.
(
i
)
1
2
I
ω
0
2
=
1
2
C
θ
m
a
x
2
.......(ii)
From equation (i) and (ii)
θ
max
=
N
A
B
Q
√
C
I
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