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JEE Advanced 2020 Full Test 4 Paper 2
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© examsnet.com
Question : 31
Total: 54
What volume in
m
L
of
0.5
M
acidified potassium permanganate solution can completely oxidize
523.15
×
10
−
3
moles of
S
n
2
+
ions to
S
n
4
+
ions?
M
n
O
4
−
+
S
n
2
+
+
H
+
⟶
M
n
2
+
+
S
n
4
+
+
H
2
O
Your Answer:
Validate
Solution:
Moles of
S
n
2
+
=
523.15
×
10
−
3
Moles of
M
n
O
4
−
required
=
2
5
×
523.15
×
10
−
3
Volume
=
2
5
×
523.15
×
10
−
3
×
1000
0.5
=
418.52
m
L
© examsnet.com
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