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JEE Advanced 2020 Full Test 6 Paper 1
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© examsnet.com
Question : 15
Total: 54
A large concave mirror with a radius of curvature of
0.5
m
is placed on a horizontal plate. We pour a small amount of water into the mirror and place on it a plano-convex lens with a radius of curvature of
1.0
m
whose plane side just covers the water. Then we place a point light source above this set-up at a height of
0.3
m
. The distance (in metres) from the object where the final image is formed will be
x
90
. Find
x
given that the refractive index of water is
4
3
and the refractive index of glass is
1.50
.
Your Answer:
Validate
Solution:
1
f
1
=
(
1.5
−
1
)
(
1
1
)
=
0.5
m
−
1
1
f
2
=
(
4
3
−
1
)
(
1
0.5
)
=
1
3
×
1
0.5
=
2
3
m
−
1
Power of the system
P
=
2
P
1
+
2
P
2
+
P
m
=
2
×
0.5
+
2
×
2
3
+
1
0.25
=
1
+
4
3
+
4
=
3
+
4
+
12
3
=
19
3
Focal length of equivalent mirnor
=
−
3
19
m
1
v
+
1
−
0.3
=
1
−
3
∕
19
1
v
=
1
0.3
−
19
3
=
10
3
−
19
3
=
−
9
3
=
−
3
v
=
−
1
3
m
⇒
d
=
−
3
10
+
1
3
=
1
30
⇒
1
30
=
x
90
⇒
x
=
3
m
© examsnet.com
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