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JEE Advanced 2020 Full Test 7 Paper 1

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Question : 6

Total: 54

A solid sphere of radius r and mass m is released from point A on a vertical circular surface of radius 5r which has sufficient friction in part AB. Part BCD is smooth and h is the maximum height attained by the centre of the sphere from point C in part CD. The total energy and the kinetic energy at this height is T and K, respectively (assume that a lowest point C of the circular path as reference point for potential energy). Then

h=(‌
31
7
)r
T=5mgr
K=(‌
4
7
)mgr
The friction force on the sphere just before point B is ‌
2√3mg
5
.

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