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JEE Advanced 2020 Full Test 7 Paper 1
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© examsnet.com
Question : 9
Total: 54
Two identical capacitors are connected as shown and having initial charge
Q
0
. Separation between plates of capacitors is
d
0
. Suddenly the left plate of upper capacitor and right plate of lower capacitor start moving with speed
v
towards left while other plate of capacitor remains fixed.
The value of currents in the circuit be
Q
0
V
d
0
The value of current in the circuit be
Q
0
V
2
d
0
The value of charge on lower capacitor at time
t
is
Q
0
V
d
0
t
The value of charge on lower capacitor at time
t
is
Q
0
(
d
0
+
v
t
)
d
0
Validate
Solution:
q
1
+
q
2
=
2
Q
0
.
.
.
C
1
=
A
ε
0
d
0
+
v
t
,
C
2
=
A
ε
0
d
0
v
t
∴
C
1
C
2
=
d
0
−
v
t
d
0
+
v
t
=
q
1
q
2
∴
from
(
i
)
and
(
i
i
)
q
2
=
q
0
(
d
0
+
v
t
)
d
0
© examsnet.com
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