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JEE Advanced 2020 Paper 1
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Question : 30
Total: 54
The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has smaller ionic radius. Choose the correct statement(s).
[JEE Adv 2020 P1]
The empirical formula of the compound is MX
The cation M and anion X have different coordination geometries
The ratio of M-X bond length to the cubic unit cell edge length is 0.866
The ratio of the ionic radii of cation M to anion X is 0.414
Validate
Solution:
Contribution of
M
=
1
2
×
2
=
1
Contribution of
X
=
1
4
×
4
=
1
Formula = MX
Distance between
M
and
X
=
√
a
2
4
+
a
2
2
=
√
3
4
a
=
√
3
2
a
= 0.866 a
Both cation and anion have same co-ordination number, i.e., 8.
Assuming, anions are in contact, the ratio of ionic radii of cation M to anion X is 0.732, the minimum radius ratio for a cubical void.
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