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JEE Advanced 2023 Paper 1 Solutions
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© examsnet.com
Question : 15
Total: 51
Match the temperature of a black body given in List-I with an appropriate statement in List-II, and choose the correct option.
[Given: Wien's constant as
2.9
×
10
−
3
m
−
K
and
h
c
e
=
1.24
×
10
−
6
V
−
m
]
List-I
List-II
(P)
2000
K
(1) The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work
(Q)
3000
K
(2) The radiation at peak wavelength is visible to human eye.
(R)
5000
K
(3) The radiation at peak emission wavelength will result in the widest central maximum of a single slit diffraction.
(S)
10000
K
(4) The power emitted per unit area is
1
/
16
of that emitted by a blackbody at temperature
6000
K
.
(5) The radiation at peak emission wavelength can be used to image human bones.
P
→
3
,
Q
→
5
,
R
→
2
,
S
→
3
P
→
3
,
Q
→
2
,
R
→
4
,
S
→
1
P
→
3
,
Q
→
4
,
R
→
2
,
S
→
1
P
→
1
,
Q
→
2
,
R
→
5
,
S
→
3
Validate
Solution:
List-I
List-II
(P)
2000
K
λ
m
T
=
b
λ
m
=
b
T
=
2.9
×
10
−
3
2000
=
1.45
×
10
−
6
m
=
1450
nm
(Q)
3000
K
λ
m
T
=
b
⇒
λ
m
=
2.9
×
10
−
3
3000
=
966.66
nm
(R)
5000
K
λ
m
T
=
b
⇒
λ
m
=
2.9
×
10
−
3
5000
=
580
nm
(S)
10000
K
λ
m
T
=
b
⇒
λ
m
=
2.9
×
10
−
3
10
,
000
=
290
nm
List-II
(1)
λ
th
=
h
c
φ
=
1.24
×
10
−
6
4
=
0.31
×
10
−
6
m
=
310
nm
As,
λ
≤
λ
th
S
→
1
(2)
400
<
λ
<
700
nm
R
→
2
(3) Central maxima is widest for maximum wavelength
⇒
P
→
3
(4)
σ
A
(
T
1
)
4
=
1
16
σ
A
T
2
4
⇒
T
1
=
1
2
T
2
=
3000
K
Q
→
4
(5) For imaging bones
X
-rays are used
(
1
−
10
nm
)
None of the options in List-II
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