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Test Index
Basics of Organic Chemistry
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Section:
Chemistry
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© examsnet.com
Question : 1
Total: 39
Match the reactions in List-I with the features of their products in List-II and choose the correct option.
List-I
List-II
(P)
‌
(
−
)
−
1
−
Bromo
−
2
−
ethylpentane
‌
(single enantiomer)
‌
‌
aq
.
NaOH
─
─
─
─
─
─
─
â–¶
S
N
‌
2 reaction
(1)
Inversion of configuration
(Q)
‌
(
−
)
−
2
−
Bromopentane
‌
(single enantiomer)
‌
‌
aq.
‌
NaOH
─
─
─
─
─
─
─
─
â–¶
S
N
2
‌
reaction
‌
(2)
Retention of configuration
(R)
(
−
)
−
3
−
Bromo
−
3
−
methylhexane
(
single
‌
enantiomer
)
‌
‌
aq.
‌
NaOH
─
─
─
─
─
─
─
─
â–¶
S
N
2
‌
reaction
‌
(3)
Mixture of enantiomers
(S)
(4)
Mixture of structural isomers
(5)
Mixture of diastereomers
[JEE Adv 2023 P1]
P
→
1
;
Q
→
2
;
R
→
5
;
S
→
3
P
→
2
;
Q
→
1
;
R
→
3
;
S
→
5
P
→
1
; Q
→
2
; R
→
5
;
→
→
4
P
→
2
;
Q
→
4
; R
→
3
;
S
→
5
Validate
Solution:
(P) Configuration at chiral carbon is same.
P
→
2
[reaction does not occur at chiral carbon]
(Q) Configuration at chiral carbon changes.
Q
→
1
(R)
S
N
1
→
Mixture of enantiomers formed.
R
→
3
∴
So mixture of diastereomers are formed.
S
→
5
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