Point of contact : (8,16) Equation of tangent ⇒y=x+8 ∴ Slope (m)=1 i.e. Matching with (i) of column 2 my=m2x+a y=x+8 Hence, m=1 and a=8 Matching with (P) of column 3:(‌
a
m2
,‌
2a
m
) ⇒(‌
8
1
,‌
2×8
1
)=(8,16) Matching with column 1 1) x2+y2−a2=0⇒82+162−82≠0 2) x2+a2y2−a2=0⇒82+(82×162)−82≠0 3) y2=4ax⇒162−4(8)(8)=0 Hence, equation of curve ⇒y2=4ax Point of contact: (‌