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JEE Advanced Model Paper 12 with solutions for online practice
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© examsnet.com
Question : 18
Total: 60
A circular conducting loop of Radius '
r
0
' and having resistance per unit length ’λ ’ as shown in the figure is placed in a magnetic field B which is constant in space and time. The ends of the loop are crossed and pulled in opposite directions witha velocity ’υ' such that the loop always remains circular and the radius of the loop goes on decreasing then
Radius of the loop changes with r =
r
0
-
√
t
π
EMF induced in the loop as a function of time is 2Bυ
(
r
0
−
υ
t
π
)
Current induced in the loop is
B
υ
2
π
λ
Current induced in the loop is
B
υ
π
λ
Validate
Solution:
The length of the loop at any time is l = 2π
r
0
- 2υt
∴ radius of the loop =
r
0
-
υ
t
π
emf induced =
−
d
d
t
(Bπ
r
2
) = 2Bυ
(
r
0
−
υ
t
π
)
∴ induced current =
emf
l
λ
=
8
υ
π
λ
© examsnet.com
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