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JEE Advanced Model Paper 16 with solutions for online practice
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© examsnet.com
Question : 11
Total: 69
A black mineral (A) in solid state is fused with KOH and
K
N
O
3
and the mixtureextracted with water to get a green coloured solution (B). On passing
C
O
2
gas throughthe solution the colour changes to pink with a black residue (C). Which of thefollowing is/are correct
The pink colouration is decolourised by acidified ferrous sulphate solution
The black residue is same as compound (A)
When
O
3
is passed through the green colour solution is changes to pink.
Shape of the anion of pink substance is tetrahedral
Validate
Solution:
Black mineral (A) is
M
m
O
2
2
K
N
O
3
→ 2
K
N
O
2
+
O
2
2
M
N
O
2
+ 4KOH +
O
2
Δ
→
2
K
2
M
n
O
4
green
+
2
H
2
O
3
K
2
M
n
O
4
+
2
C
O
2
→
2
K
M
n
O
4
pink
+
2
K
2
C
O
3
+
M
n
O
2
Black
residue
2
K
2
M
n
O
4
+
O
3
+
H
2
O
→
2
K
M
n
O
4
+ 2KOH +
O
2
M
n
O
4
−
ion is tetrahedral
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