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JEE Advanced Model Paper 17 with solutions for online practice
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© examsnet.com
Question : 1
Total: 60
A furnace has a two layered wall as shown schematically. Each layer has the same area ofcross section. The temperature θ at the interface of two layers can be reduced by
increasing the thermal conductivity of outer layer
decreasing the thermal conductivity of inner layer
by increasing the thickness of inner layer
by decreasing the thickness of outer layer
Validate
Solution:
Rate of heat flow H =
800
−
80
(
l
t
K
i
A
)
+
(
l
0
K
0
A
)
which is also equal to
800
−
θ
(
l
t
K
i
A
)
. Using these tworelations we get , θ = 800 -
720
1
+
(
K
i
K
0
)
(
l
0
l
t
)
. Thus one can reduce the temperature at theinterface by any of the four options given.
© examsnet.com
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