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JEE Advanced Model Paper 20 with solutions for online practice
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© examsnet.com
Question : 11
Total: 57
Match the following:
Column-I
Column-II
A) Nitrobenzene → azobenzene
P)
L
i
A
l
H
4
B) Aniline → phenyl isocyanide
Q)
N
a
N
O
2
+ HCl +
C
u
2
C
l
2
C) Aniline→ chlorobenzne
R)
C
H
C
l
3
+ KOH
D) Ethylamine → ethanol
S)
N
a
N
O
2
+
H
C
l
a
q
T) Zn + NaOH +
C
H
3
O
H
A - P , T ; B - R ; C - Q ; D - S
A - P , T ; B - Q , R ; C - Q ; D - S
A - P , T ; B - R ; C - Q , R ; D - S
A - P , T ; B - R ; C - Q ; D - Q , S
Validate
Solution:
C
6
H
5
N
O
2
L
i
A
l
H
4
or
Z
n
+
N
a
O
H
+
C
H
3
O
H
→
C
6
H
5
N
= N -
C
6
H
5
C
6
H
5
N
2
N
a
N
O
2.
H
C
l
→
C
6
H
5
-
+
N
≡ N -
C
6
H
5
- Cl
Aniline → carbyl amine
C
H
3
C
H
2
N
H
2
N
a
N
O
2.
H
C
l
→
C
H
3
C
H
2
-
+
N
2
−
N
2
→
C
H
3
C
H
2
H
2
O
−
H
→
C
2
H
5
O
H
© examsnet.com
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