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JEE Advanced Model Paper 20 with solutions for online practice
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© examsnet.com
Question : 48
Total: 57
An object AB is placed on the principal axis in front of aconvex mirror of radius of curvature 50 cm. Assumeparaxial rays for image formation.
Column-I
Column-II
A) First image by refraction through the glass slab
P) Erect with respect to AB
B) Image by mirror
Q) Inverted with respect to AB
C) Final image of the object
R) + 2/3
D) Magnification of the final image
S) + 1/3
T) + 1
A - P ; B - Q ; C - P ; D - S
A - P ; B - P ; C - Q ; D - S
A - P ; B - P ; C - P ; D - S
A - P ; B - P ; C -P ; D - Q
Validate
Solution:
Image by slab
m
1
= + 1
Shift = 6
(
1
−
2
3
)
= 2 cm towards the slab
mirror
1
v
+
1
−
50
=
2
−
50
, v =
50
3
cm
m
2
=
−
v
u
=
−
+
50
3
−
50
=
+
1
3
,
m
3
= + 1
m =
m
1
m
2
m
3
=
1
3
© examsnet.com
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