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JEE Advanced Model Paper 3 with solutions for online practice
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© examsnet.com
Question : 24
Total: 60
A bottle of
H
2
O
2
is labeled as 10 Volumes
H
2
O
2
. 112 ml of this solution of
H
2
O
2
is required to titrate exactly 0.04 M acidified solution of
K
M
n
O
4
. Volume of
K
M
n
O
4
required in litres approximately is
Your Answer:
Validate
Solution:
Normality =
10
5.6
= 1.78
Milli equivalents of
H
2
O
2
= milliequivalents of
K
M
n
O
4
1.78 × 112 = 0.04 × 5 × volume in ml
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